function getSkypeStatusIcon($username) {
$status = getSkypeStatus($username);
echo '
';
}


I have one graphic with both a normal and active state in the image which are referencing each status code.
I have the image loaded as a background image in css and a transparent button overlaid so that when the user hovers their mouse it allows the graphic to switch (sliding doors css) to a hover state.

The problem is that the script does not seem to update the image code now? Any ideas? It works perfectly the normal way.

Thanks!,
Shane

<?php
function getSkypeStatus($username) {
$remote_status = fopen ('http://mystatus.skype.com/'.$username.'.num', 'r');
if (!$remote_status) {
return '0';
exit;
}
while (!feof ($remote_status)) {
$value = fgets ($remote_status, 1024);
return trim($value);
}
fclose($remote_status);
}
function getSkypeStatusIcon($username) {
$status = getSkypeStatus($username);
echo '
‘;
}
getSkypeStatusIcon(‘MY_USERNAME’);?>

Other issues to consider are your hosts security and the platform or CMS which you are using to host your content. We have used it on several developments with no issue, but please note we don’t take credit for the script. It was created by another party, so use it at your own risk.

But I dont have fopen on in my php.ini, last time I did this my server was hacked sometime after so I dont really want to.

I was wondering if there is any way around this.